Question

Ba^4•(2ba^4)^-3
The answer key says 1/8b^2a^8 but I don't understand how they got that.

Answer 1

`ba^4\cdot(2ba^4)^(-3)=(ba^4)/((2ba^4)^3)=(ba^4)/(8b^3a^(12))=(1)/(8b^2a^8)`

Answer 2

`a^(4)b(2ab^(4))^(-3)`


`a^(4)b( (1)/((2a^(4)b)^(3)))`


`a^(4)b( (1)/((2a^(4)b)(2a^(4)b)(2a^(4)b)))`


`a^(4)b( (1)/(8a^(12)b^(3)))`


`(1)/(8a^(8)b^(2))`