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Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

User Cheruvian
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1 Answer

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The weight of the load is (mass) x (gravity).

The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

The power is (work)/(time) =

(mass) x (gravity) x (distance) / (time) =

(500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

(500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

(500 x 9.8 x 12 / 1) newton - meter / sec =

(500 x 9.8 x 12 / 1) joule / sec =

58,800 watts

= 58.8 kW

= about 78.8 horsepower


User GunnarK
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