Givens.
• The weight force is 763.91 N.
,
• The speed is 1.10 m/s.
First, find the mass using the formula for weight force.
Where w = 763.91 N and g = 9.81 m/s^2.
![\begin{gathered} 763.91N=m\cdot9.81\cdot(m)/(s^2) \\ m=(763.91N)/(9.81\cdot(m)/(s^2)) \\ m\approx77.87\operatorname{kg} \end{gathered}]()
Once we have the mass of the woman, we can find the kinetic energy.
Use the kinetic energy formula.
![K=(1)/(2)mv^2]()
Where m = 77.87 kg and v = 1.10 m/s.
![\begin{gathered} K=(1)/(2)\cdot77.87\operatorname{kg}\cdot(1.10\cdot(m)/(s))^2 \\ K=38.94\operatorname{kg}\cdot1.21\cdot(m^2)/(s^2) \\ K\approx47.12J \end{gathered}]()
Therefore, the kinetic energy is 47.12J.