Question

Please help me with parts a, b, and c of thos problem!!

Answer 1

We have the following:

The formula that corresponds to the calculation of the population is as follows

`P=A\cdot(1+r)^t`

Where A is the population of 952 108 000 inhabitants, r is the growth rate and t is the time elapsed

a.

2000

`\begin{gathered} t=2000-1996=4 \\ P=952,108,000\cdot(1+0.013)^4=1002591447.8\cong1,002,600,000 \end{gathered}`

2010

`\begin{gathered} t=2010-1996=14 \\ P=952,108,000\cdot(1+0.013)^(14)=1140823475.4\cong1,140,800,000 \end{gathered}`

b.

In this case what we must do is replace by 10, which is the equivalent in years of a decade in the part of the equation that corresponds to growth

`\begin{gathered} (1+0.013)^(10)=1.13787 \\ 1.13787-1=0.1378 \end{gathered}`

That is, the growth is approximately 13.78%

c.

In this case, we must calculate until 2000 with the percentage of 1.3% and then from 2000 until 2010 calculate with the new growth rate

A then would be the population calculated in part a, that is, 1,002,600,000 and t would be 10 (2010 - 2000)

replacing

`P=1,002,600,000\cdot(1+0.01)^(10)=1107494142.9\cong1,107,500,000`

Therefore with the new growth rate the population in India in 2010 would be 1,107,500,000