Question

One number is seven more than twice another. If their sum is decreased by nine, the result is thirteen. Find the numbers.

Answer 1

x = 2y + 7
(x + y) - 9 = 13

((2y + 7) + y) - 9 = 13
3y + 7 - 9 = 13
3y = 13 + 9 - 7
3y = 15
y = 15 / 3
y = 5

x = 2y + 7
x = 2*5 + 7
x = 10 + 7
x = 17

Answer 2

this one was difficult one but is made to equations like such.
x+7=2y
x+y-9=13
using substitution i came to
x(the first number)=12.333
y(the second number)=9.667
hope i helped