20.9k views
3 votes
What is the standard form of the equation for this circle 4, -5 radius 5.5

User Salines
by
7.5k points

1 Answer

0 votes
Standard form of equation of a circle:

(x - a)^2 + (y -b)^2 = r ^2.

Where centre = (a , b)
r = radius.
Centre (4 , -5) = (a , b) , a = 4, b = -5.
r = 5.5.

(x - 4)^2 + (y - -5)^2 = 5.5^2
(x - 4)^2 + (y +5)^2 = 5.5^2 Expand brackets, and use your calculator

x^2 - 8x + 16 + y^2 +10y + 25 = 30.25
x^2 - 8x + y^2 +10y + 25 +16 - 30.25 = 0
x^2 - 8x + y^2 +10y - 10.25 = 0.
x^2 + y^2 -8x +10y - 10.25 = 0. That's the equation of the circle.

or 10.25 = 10 /1/4 = 41/4

x^2 + y^2 -8x +10y - 41/4 = 0 Multiply both sides of the equation by 4.

4x^2 + 4y^2 -32x +40y - 41 = 0

Cheers.
User Vincent Marchetti
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories