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5 votes
How do i solve 1-6Log(6x-7)=13 ????

2 Answers

6 votes

D:6x-7>0\\ D:6x>7\\ D:x>(7)/(6)\\\\ 1-6\log(6x-7)=13 \\ 6\log(6x-7)=-12\\ \log(6x-7)=-2\\ 10^(-2)=6x-7\\ 6x-7=(1)/(100)\\ 600x-700=1\\ 600x=701\\ x=(701)/(600)
User Patrick Hurst
by
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1 vote

1-6\log { \left( 6x-7 \right) } =13\\ \\ -6\log { \left( 6x-7 \right) } =12


\\ \\ \frac { -6\log { \left( 6x-7 \right) } }{ -6 } =\frac { 12 }{ -6 } \\ \\ \log { \left( 6x-7 \right) } =-2


\\ \\ { 10 }^( -2 )=6x-7\\ \\ 6x-7=\frac { 1 }{ 100 } \\ \\ 6x=7+\frac { 1 }{ 100 }


\\ \\ 6x=\frac { 700 }{ 100 } +\frac { 1 }{ 100 } \\ \\ 6x=\frac { 701 }{ 100 }


\\ \\ \frac { 1 }{ 6 } \cdot 6x=\frac { 1 }{ 6 } \cdot \frac { 701 }{ 100 } \\ \\ x=\frac { 701 }{ 600 }
User Simon Forsberg
by
8.0k points

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