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39 votes
Simplify completely: 12x11y · 1848062" y? 16O 6x^y? V6xO 6x"y? 6xO 216'ya

User SimplyPanda
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1 Answer

17 votes
17 votes

Given:


\sqrt[]{12x^(11)y^6}.\sqrt[]{18y^8}

To simplify this, we can follow the steps below


\sqrt[]{12x^(11)y^6}.\sqrt[]{18y^8}=\sqrt[]{12*18* x^(11)* y^6* y^8}

This can be simplified further


\sqrt[]{216* x^(11)* y^(14)}

Then we will obtain


\sqrt[]{216\text{ }}\text{ x }\sqrt[]{x^(11)}\text{ x}\sqrt[]{y^(14)}

=>


6\sqrt[]{6}* x^{(11)/(2)}* y^{(14)/(2)}

=>


6\sqrt[]{6}\text{ }*(x^{5+(1)/(2)})* y^7

=>


6\sqrt[]{6}\text{ }* x^5* x^{(1)/(2)}* y^7

=>


6\sqrt[]{6}\text{ }* x^5*\sqrt[]{x}\text{ }* y^7

=>


6x^5y^7\sqrt[]{6x}

User Steve Paulo
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