Question

How do i graph the parabolas y = 1/32x^2

Answer 1

`y=(1)/(32)x^2 \\ \\x=-16 \Rightarrow y=(1)/(32) *(-16)^2=(1)/(\\ot32^1)*\\ot256^8=8\\ \\x=-8 \Rightarrow y=(1)/(32) *(-8)^2=(1)/(\\ot32^1)*\\ot64^2=2\\ \\x=0 \Rightarrow y=(1)/(32) *(0)^2=(1)/(\\ot32^1)*0=0 \\ \\x=8 \Rightarrow y=(1)/(32) *(8)^2=(1)/(\\ot32^1)*\\ot64^2=2 \\ \\x= 16 \Rightarrow y=(1)/(32) *( 16)^2=(1)/(\\ot32^1)*\\ot256^8=8`