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(20-r)^1/2=r what is the square root of this equation

(20-r)^1/2=r what is the square root of this equation
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(20-r)^1/2=r what is the square root of this equation

User Keli
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1 Answer

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20-r=r^2
r^2+r-20=0
(r+5)(r-4)=0
r=4,-5
User Sep
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