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Three terms , 19-6x , 2 + 4x , 6x + 1, are in arithmetic progression . a) Calculate the value of x .
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Three terms , 19-6x , 2 + 4x , 6x + 1, are in arithmetic progression .

a) Calculate the value of x .

User Rmflight
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1 Answer

3 votes
so therfor from 19-6x to 2+4x the diffence if the same as the diffence between 2+4x an d6x+1


so (2+4x)-(19-6x)=(6x+1)-(2+4x)
add like terms
2+4x-19+6x=6x+1-2-4x
10x-17=2x-1
add 17 to both sdies
10x-2x+16
subtract 2x form both sdies
8x=16
divide boht sdie syb 8
x=2

x=2
therfor the terms are
7, 10, 13
User Jessie Emerson
by
7.5k points
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