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Factor the expression 15x-^2-10x-5

User Sturm
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2 Answers

3 votes
15x^2 - 10x - 5
(3x + 1) (5x - 5)

If it tells you to solve it, set each part in parentheses and solve. What you end up will be your 2 final answers.
User Keatinge
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3 votes

15x^2-10x-5=0\\ \\ a=15, \ \ b=-10 \ \ c=-5\\ \\ \Delta = b^(2)-4ac = (-10)^(2)-4* 15* (-5)= 100+300=400\\ \\x_(1)=(-b-√(\Delta ))/(2a) =(10- √(400))/(2*15)=(10-20)/(30)= (-10)/(30)=-(1)/(3)\\ \\x_(2)=(-b+√(\Delta ))/(2a) =(10+ √(400))/(2*15)=(10+20)/(30)= (30)/(30)=1 \\ \\ \ 15x^2-10x-5=15(x+ (1)/(3))(x-1)= (15x+ (1)/(3)*15)(x-1)=(15x+5)(x-1)\\ \\ Answer :15x^2-10x-5 =(15x+5)(x-1)
User Novice C
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