Question

What's the answer too x+7/7x+35*x^2-3x-40/x-8

Answer 1

`(x+7)/(7x+35)\cdot(x^2-3x-40)/(x-8)=(*)\\\\x^2-3x-40=0\\a=1;\ b=-3;\ c=-40\\\Delta=b^2-4ac;\ x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\\\\\Delta=(-3)^2-4\cdot1\cdot(-40)=9+160=169;\ \sqrt\Delta=√(169)=13\\\\x_1=(3-13)/(2\cdot1)=(-10)/(2)=-5;\ x_2=(3+13)/(2\cdot1)=(16)/(2)=8\\\\x^2-3x-40=(x+5)(x-8)\\\\(*)=(x+7)/(7(x+5))\cdot((x+5)(x-8))/(x-8)=(x+7)/(7)=(x)/(7)+(7)/(7)=(1)/(7)x+1\\\\D:x\\eq-5\ \wedge\ x\\eq8`