Question

The area of a rectangle is 32 in² and its length is 4 inches

a) Find the width
b) Find the perimeter

Answer 1

A = lw
32 = 4(w)
32 = 4w
4 4
8 = w

P = 2l + 2w
P = 2(8) + 2(4)
P = 16 + 8
P = 24in

Answer 2

A) The with is 8 inches. You would do 32/4 to get your answer
B) The perimeter is 12. P=l+w so P=8+4 which is 12.(P stands for perimeter