39.1k views
2 votes
Y=6x-12
Y=-9x+3
Help me solve

2 Answers

5 votes
So,

Let's solve this algebraically.

Subtract 6x from both sides of the first equation.
y - 6x = -12

Substitute -9x + 3 for y in the first equation.
-9x + 3 - 6x = -12

Collect Like Terms
-15x + 3 = -12

Subtract 3 from both sides
-15x = -15

Divide both sides by -15
x = 1

Substitute 1 for x in the first original equation.
y = 6(1) - 12
y = 6 - 12
y = -6

Check
-6 = 6(1) - 12
-6 = 6 - 12
-6 = -6 This checks.

-6 = -9(1) + 3
-6 = -9 + 3
-6 = -6 This also checks.

S = {(1,-6)}
User Jpgerek
by
7.6k points
4 votes
First you'll need to solve for x. To do this, put both equations equal to each other
6x-12=-9x+3
Add 9x to both sides
15x-12=3
Add 12 to both sides
15x=15
Divide both sides by 15
x=1
Next, substitute x into one of the equations to find y
y=(6*1)-12
y=6-12
y=-6
User Artharos
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories