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What is the zero for 2x2-7=4

User Sergiogx
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2 Answers

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2x² - 7 = 4
+7 +7
2x² = 11
2 2
x² = 5 1/2
x = √5 1/2
User LJG
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4 votes
2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345
User Ana Franco
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