Question

Calculate the wavelength of a photon of light with a frequency of 6.15x10^14Hz

Answer 1

Answer:
`\text{The wavelength of the photon of light = }4.88\text{ }*10^(-7)m`Explanations:

The relationship between the speed, wavelength and frequency of light is:

`c\text{ = }\lambda f`

where c is the speed of light

λ is the wavelength

and f is the frequency

From the question:

`f\text{ = }6.15\text{ }*10^(14)Hz`
`c\text{ = 3 }*10^8\text{ m/s}`
`\begin{gathered} c\text{ = }\lambda f \\ \lambda\text{ = }(c)/(f) \\ \lambda=(3*10^8)/(6.15*10^(14))\text{ } \\ \lambda\text{ = }0.488*10^(-6) \\ \lambda\text{ = 4.88}*10^(-1)*10^(-6) \\ \lambda=4.88*10^(-7)m\text{ } \end{gathered}`

Therefore, the wavelength of the photon of light is

`4.88\text{ }*10^(-7)m`