Question

A train leaves the station at time x=0. Traveling at a constant speed, the train travels 334 km in 3.4 h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph.

Answer 1

First, let's round the distance to the nearest 10 km.

The distance is 334 km, so the nearest 10 km is 330 km.

Then, let's round the time to the nearest whole hour.

The time is 3.4 h, so rounding to the nearest whole hour we have 3 hours.

Now, let's represent the distance y and time x using an equation

To do so, let's use the following equation for distance:

`\begin{gathered} \text{distance}=\text{speed}\cdot\text{time} \\ \text{speed}=\frac{\text{ distance}}{\text{time}}=(330)/(3)=110\text{ km/h} \\ \\ y=110\cdot x \end{gathered}`

Now, to create a table, let's choose some values of x and then calculate the corresponding values of y:

Graphing these ordered pairs (x, y) into the cartesian plane, we have: