Question

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?

A. 2/11
B. 1/6
C. 2/33
D. 16/33

Answer 1

D. 16/33

because there are 28 g/g pairs, 6 b/b pairs, and 32 g/b pairs. In total 66 pairs, and of those pairs 32/66 are 1 girl and 1 boy, reduced is 16/33.

Answer 2

Probability is all about multiplying fractions.

The first fraction is the probability of picking a girl.. so how many of the 12 total children are girls. (8/12)

The second fraction is the probability of picking a boy.. so how many of the 11 remaining children are boys. (4/11)

8/12 X 4/11 = 8/33 -> this isn't even an option but I'm like 10000% this is the right answer..

I started off this answer feeling so confident lol. good luck.