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Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x.

ax + bx - c = 0

2 Answers

2 votes

ax+bx-c=0\\ x(a+b)=c\\ x=(c)/(a+b)
User Mikael Nitell
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4 votes

ax+bx-c=0 \ \ \ |+c \\ ax+bx=c \\ (a+b)x=c \ \ \ |/ (a+b), a+b \\ot= 0 \\ \boxed{x=(c)/(a+b)}
User Viraj
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8.4k points