Write an equation of a line that is parallel to the line whose equation is 3y=x+6 and that passes through the point (-3,4).

Question

asked Jul 11, 2016 187k views

1 Answer

Jedesah · Answer 1 · 2016-07-16T23:46:49+0000

The standard form of this equation is

y=(1)/(3)x+2

The slope of two parallel lines i the same, so the slope of the line we're looking for is also
(1)/(3)

Since the line passes through
(-3,4)

, the equation is:

(y-4)=(1)/(3)(x+3)

$\boxed{y=(1)/(3)x+5}$