Question

Write an equation of a line that is parallel to the line whose equation is 3y=x+6 and that passes through the point (-3,4).

Answer 1

The standard form of this equation is


`y=(1)/(3)x+2`

The slope of two parallel lines i the same, so the slope of the line we're looking for is also
`(1)/(3)`

Since the line passes through
`(-3,4)`, the equation is:


`(y-4)=(1)/(3)(x+3)`


`\boxed{y=(1)/(3)x+5}`