Question

How do I write this equation in standard form
Y +7 =5/4(x-6)

Answer 1

y + 7 = 1 1/4(x - 6)
y + 7 = 1 1/4(x) - 5/4(6)
y + 7 = 1 1/4x - 7 1/2
+ 7 1/2 +7 1/2
y + 14 1/2 = 1 1/4x
y = mx + b
y = 1 1/4x + 14 1/2

Answer 2

By "standard" I assume you mean "slope-intercept."

The form you have it in is "point-slope"

"slope intercept form" comes in the form
`y=mx+b`

Therefore the form would be:


`y=(5)/(4)x-(15)/(2)-7`


`\boxed{y=(5)/(4)x-(29)/(2)}`