Question

Complete by solving the square:

2x^2−9x+9=0

Answer 1

ax² + bx + c = 0
2x² - 9x + 9 = 0
2x² + (-9x) + 9 = 0
x = -b +/- √b² - 4ac
2a
x = -(-9) +/- √9² - 4(2)(9)
2(2)
x = 9 +/- √81 - 72
4
x = 9 +/- √9
4
x = 9 +/- 3
4
x = 9 + 3 x = 9 - 3
4 4
x = 12 x = 6
4 4
x = 3 x = 3/2 or 1 1/2

Answer 2

`2( x^(2) -4.5x)+9=0`


`2[(x-2.25) ^(2)-5.0625]+9=0`


`2(x-2.25) ^(2)-10.125+9=0`


`2(x-2.25) ^(2)-1.125=0`


`(x-2.25) ^(2)=0.5625`


`x-2.25= √(0.5625)`


`x-2.25=0.75`


`x-2.25=-0.75`


`x=3` or
`x=1.5`

Hope this helped