Question

9/35 x 7/16 x 20/21 =

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Answer 1

`(9)/(35)\cdot(\\ot7^1)/(16)\cdot(20)/(\\ot21_3)=(9)/(35)\cdot(1)/(\\ot16_4)\cdot(\\ot20^5)/(3)=(\\ot9^3)/(35)\cdot(1)/(4)\cdot(5)/(\\ot3_1)=(3)/(\\ot35_7)\cdot(1)/(4)\cdot(\\ot5^1)/(1)\\\\=(3)/(7)\cdot(1)/(4)\cdot(1)/(1)=(3\cdot1\cdot1)/(7\cdot4\cdot1)=(3)/(28)`