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Solve for a: a(a-3) =100

User Reshure
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1 Answer

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a(a-3) =100\\ a^2-3a-100=0\\ \Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\ √(\Delta)=\sqr{409}\\ a_1=(-(-3)-√(409))/(2\cdot1)=(3-√(409))/(2)\\ a_2=(-(-3)+√(409))/(2\cdot1)=(3+√(409))/(2)
User Martinlasek
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