Question

1.5kg iron horse shoe initially at 600°c,it dropped into a bucket containing 20kg of water at 25°c.what is the final temperature. ( ignore heat capacity of the container )and assumed that a negligible amount of water boils always .(SHC of water 4186jkg°c,SHC of iron is 448jkg°c

Answer 1

Let final temperature be θ
You have not given values for specific heat capacities, but any text-book will give the figures as
Iron = 460 J/kgK
Water = 4187 J/KgK
Heat lost by horse shoe = heat gained by water (mC δt)
1.5 x 460 x (600 - θ ) = 20 x 4187 x ( θ - 25)
690 ( 600 - θ ) = 83740 ( θ - 25)
414000 - 690 θ = 83740 θ - 2093500
2507500 = 84430 θ
θ = 29.7 C
Final temperature of horse shoe and water is 29.7 C