Question

the sum of three numbers is 61. the second number is 6 times the first. and the third number is 5 more than the second. find the numbers

Answer 1

`x-the\ first\ number\\6x-the\ second\ number\\6x+5-the\ third\ number\\\\(x)+(6x)+(6x+5)=61\\x+6x+6x+5=61\\13x+5=61\ \ \ \ |subtract\ 5\ from\ both\ sides\\13x=56\ \ \ \ |divide\ both\ sides\ by\ 13\\\boxed{x=(56)/(13)\to x=4(4)/(13)-the\ first\ number}\\\boxed{6x=6\cdot(56)/(13)=(336)/(13)=25(11)/(13)-the\ second\ number}\\\boxed{6x+5=25(11)/(13)+5=30(11)/(13)-the\ third\ number}`