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If t is a number greater than 1, then t^2 is how ,much greater than t?
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If t is a number greater than 1, then t^2 is how ,much greater than t?

User Ashleigh
by
8.8k points

1 Answer

0 votes

t^(2) -1 >0
Therefore,
t(t-1)>0

Answer:
t(t-1)
User Billyhole
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8.6k points
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