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If the coordinates of a parallelogram are Q(3, -2), R(7, -2), S(9,3), and T(5,3), the area of the parallelogram is:A. 10 units²B. 20 units²C. 30 units²D. 40 units²

User BrianCas
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1 Answer

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14 votes

SOLUTION:

Given that the coordinates of a parallelogram are Q(3, -2), R(7, -2), S(9,3), and T(5,3), we are to find the area of the parallelogram.

To find the base QR;

Q(3, -2) and R(7, -2)

Base = 7 - 3 = 4 units

To find the height of the Parallelogram;

T(5, 3) and Q(3, -2)

Height = 3 - (-2) = 3 + 2 = 5 units

The formula to calculate the area of a parallelogram is given as;

Area of parallelogram = base × height square units.

Area = 4 units x 5 units

Area = 20 units squared (Option B).

If the coordinates of a parallelogram are Q(3, -2), R(7, -2), S(9,3), and T(5,3), the-example-1
User Neumann
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