Question

Solve the systems by Elimination {4x−2y=−286x+2y=−2 Expressed your answer as an ordered pair.

Answer 1

We have a system of two equations and we must solve it by elimination:

`\begin{gathered} 4x-2y=-28 \\ 6x+2y=-2 \end{gathered}`

In order to do this we have to add or substract equations. For example we can add the two equations. In order to do this we have to add the left side of the first to the left side of the second and we have to do the same for the right side. Then we get:

`\begin{gathered} 4x-2y+6x+2y=-28-2 \\ 10x=-30 \end{gathered}`

Then we can divide both sides by 10:

`\begin{gathered} (10x)/(10)=-(30)/(10) \\ x=-3 \end{gathered}`

So x=-3. Then we can take the second equation and replace x with -3:

`\begin{gathered} 6\cdot(-3)+2y=-2 \\ -18+2y=-2 \end{gathered}`

And we add 18 to both sides:

`\begin{gathered} -18+2y+18=-2+18 \\ 2y=16 \end{gathered}`

And we divide both sides by 2:

`\begin{gathered} (2y)/(2)=(16)/(2) \\ y=8 \end{gathered}`

Then the answer is (-3,8).