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4x+y=23
3x-y=12 how to do do this

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\left \{ {{4x+y=23} \atop {3x-y=12}} \right. \\+---\\add\ both\ equations\\\\ 7x=35\ \ \ | divide\ by \ 7\\\\ x=5\\\\ y=23-4x=23-4*5=23-20=3
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