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⇒please help How many solutions does the equation 2(2x-10)-8= -2(14-3x) have? a.one solution b. two solutions c. no solutions d. infinitely many solutions

⇒please help How many solutions does the equation 2(2x-10)-8= -2(14-3x) have? a.one solution b. two solutions c. no solutions d. infinitely many solutions
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⇒please help

How many solutions does the equation 2(2x-10)-8= -2(14-3x) have?
a.one solution
b. two solutions
c. no solutions
d. infinitely many solutions

User JoseAndresGomezTovar
by
7.4k points

1 Answer

5 votes

2(2x-10)-8=-2(14-3x)\ \ \ | omit\ the\ bracket\\\\ 4x-20-8=-28+6x\\\\ 4x-28=-28+6x\ \ \ | subtract\ 6x\\\\ -2x-28=-28\ \ \ | add\ 28\\\\ -2x=0\ \ \ \ | divide\ by\ -2\\\\ x=0\\\\ Answer:A
User Einav Hacohen
by
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