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2+3i divided by 3-3i ( a+bi form)
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2+3i divided by 3-3i ( a+bi form)

User Michael Berry
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(2+3i):(3-3i)=(2+3i)/(3-3i)\cdot(3+3i)/(3+3i)=((2+3i)(3+3i))/((3-3i)(3+3i))=(6+6i+9i-9)/(3^2-(3i)^2)=(-3+15i)/(9+9)\\\\=(-3+15i)/(18)=-(3)/(18)+(15i)/(18)=-(1)/(6)+(5)/(6)i
User Eeq
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