Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Step-by-step explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z*\sigma+\mu \\ x=1.08*27+406 \\ x=435.16 \end{gathered}]()
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms