How do you solve 216^x-1=6

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asked Mar 26, 2016 127k views

1 vote

How do you solve
216^x-1=6

Mathematics
middle-school

Greenhoorn asked

by Greenhoorn

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2 Answers

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$216^(x-1)=6\\ ln(216^(x-1))=ln(6)\\ (x-1)ln(216)=ln(6)\\ xln(216)-ln(216)=ln(6)\\ xln(216)=ln(6)+ln(216)\\ x= (ln(6)+ln(216))/(ln(216)) \approx 1,333$

Andrei Roba answered Mar 29, 2016

by Andrei Roba

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2 votes

$216^(x-1)=6 \\ (6^3)^(x-1)=6 \\ 6^(3(x-1))=6 \\ 6^(3x-3)=6^1 \\ 3x-3=1 \\ 3x=4 \\ x=(4)/(3)$

Jonathan Carroll answered Apr 2, 2016

by Jonathan Carroll

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