Question

Simplify each equation, then solve. 1) log 2 128=x

Answer 1

`l[tex]log_(2)128=x\\\\ Formula\ for\ log:\\ log_(a)c=b\ \ \ =>\ a^b=c\\\\ 2^x=128\\\\ 2^x=2^7\\\\ x=7\\\\Solution\ is\ x=7.`[/tex]

Answer 2

`\log _( 2 ){ 128 } =x\\ \\ \log _( 2 ){ \left( { 2 }^( 7 ) \right) } =x\\ \\ 7\cdot \log _( 2 ){ 2 } =x`


`\\ \\ 7\cdot 1=x\\ \\ \therefore \quad x=7`