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At Furnace Woods School, enrollment increased from 320 students in 2006  to 349 students in 2007. What is the percent increase in enrollment? Please let me know how to do it without the computer calculations so I can do problems like these on my own

2 Answers

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Final answer:

The percent increase in enrollment at Furnace Woods School is approximately 9.06%. This is calculated by finding the difference in enrollment numbers, dividing by the original number, and then multiplying by 100 to convert to a percentage.

Step-by-step explanation:

To calculate the percent increase in enrollment at Furnace Woods School from 320 students in 2006 to 349 students in 2007, follow these steps:

  1. Find the difference in enrollment between the two years by subtracting the original amount (320) from the new amount (349). So, 349 minus 320 equals 29.
  2. To find the percent increase, you divide the difference (29) by the original number (320). So you have 29 divided by 320 which equals approximately 0.090625.
  3. Finally, multiply the result by 100 to convert it to a percentage. When you multiply 0.090625 by 100, you get 9.0625%.

Therefore, the percent increase in enrollment is approximately 9.06%.

User Effel
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Here are two slightly different ways to look at it.
Both ways do exactly the same thing.

Way #1:
Divide (the new number) by (the old number)

349 / 320 = 1.090625

Change the quotient 1.090625 to percent.

To change any number into percent, multiply it by 100, or move the decimal point 2 places to the right.

1.090625 ==> 109.06 %

The new number (349) is 109.06% of the old number (320).

But the old number was 100% of itself. So the new number
is 9.06% more than the old number was.
================================

Way #2:
How much bigger is the new number ?

(349 - 320) = 29 bigger

Divide the increase by the old number:

29 / 320 = 0.090625

Change the quotient to a percent.

0.090625 = 9.06%

The increase is 9.06% of the old number.


User GrayWizardx
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