Question

It’s homework I been stuck on the problem for 20 mins

Answer 1

The given transformation is:

`g(x)=6f(8x)+1`

What we do is to express the x in f(x) as a product and 8 and another number.

• 80=8 x 10

,

• -56=8 x -7

,

• -32 = 8 x -4

,

• 8=8 x 1

Therefore:

`\begin{gathered} g(10)=6f(8*10)+1=6f(80)+1=6(-9)+1=-14 \\ \implies x=10,g(x)=-14 \\ \\ g(-7)=6f(8*-7)+1=6f(-56)+1=6(-2)+1=-11 \\ \implies x=-7,g(x)=-11 \\ \\ g(-4)=6f(8*-4)+1=6f(-32)+1=6(5)+1=31 \\ \implies x=-4,g(x)=31 \\ \\ g(1)=6f(8*1)+1=6f(8)+1=6(7)+1=43 \\ \implies x=1,g(x)=43 \end{gathered}`

The completed table is, therefore: