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20 votes
20 votes
A man drags a 10.0 kg bag of mulch

at a constant speed, applying a
22.5 N force at 32.0°.
What is the friction force acting on the bag?
[?] N

A man drags a 10.0 kg bag of mulch at a constant speed, applying a 22.5 N force at-example-1
User BenjaminGolder
by
2.5k points

1 Answer

10 votes
10 votes

Answer:

The force of friction is 19.1 N

Explanation:

According to Newton's second law, the net force acting on the bag is equal to the product between its mass and its acceleration:

where

is the net force

m is the mass

a is the acceleration

The bag is moving at constant speed, so its acceleration is zero:

Therefore the net force is zero as well:

Here we are interested only in the forces acting along the horizontal direction, therefore the net force is given by:

where

is the horizontal component of the applied force, with

F = 22.5 N

is the force of friction

And solving for , we find

User Cian
by
3.3k points