Question

Given the reaction: C6H12O6 + 6O2 → 6CO2 + 6H2

How many molecules of C6H12O6(s ) are needed to produce 24 molecules of carbon dioxide?

Answer 1

Use the coefficients as a ratio. 1:6 = x:24. You can write these as fractions and cross multiply, 6x=24. Solve and x=4, so four molecules would be needed

Answer 2

=4moleculesC_6H_{12}O_6

Step-by-step explanation:

Hello,

In this case, since 24 molecules of carbon dioxide, and considering the given reaction, the following stoichiometric calculation turns out helpful to determine the requested molecules of C₆H₁₂O₆ that are needed:

`=24moleculesCO_2*(1molCO_2)/(6.022x10^(23)moleculesCO_2)*(1molC_6H_(12)O_6)/(6molCO_2)*(6.022x10^(23)moleculesC_6H_(12)O_6)/(1molC_6H_(12)O_6) \\=4moleculesC_6H_(12)O_6`

It is clear that Avogadro's number is needed to perform the one to six relationship between C₆H₁₂O₆ and CO₂.

Best regards.