Question

Which is an equation in point-slope form for the given point and slope? Point:(2,-6) Slope:-3/4

Answer 1

The equation for point-slope form is


`y-y_(1)=m(x-x_(1))`

m being the slope, y1 being the second point in the (2, -6) and the x1 being the first point in the (2, -6).

So the equation would look like this (for point-slope):


`y-(-6)=- (3)/(4)(x-2) \\ or \\ y+6=- (3)/(4)(x-2)`

If you're looking for slope-intercept form you can simplify the equation:


`y+6=- (3)/(4)(x-2) \\ \\ y+6=- (3)/(4)x+ (6)/(4) \\ \\ y+6-6=- (3)/(4)x+ (6)/(4)-6 \\ \\ y=- (3)/(4)x- (18)/(4)`

If you're looking for the standard form of the equation, you can take the slope-intercept equation and turn it into standard form:


`y=- (3)/(4)x- (18)/(4) \\ 4y=4(- (3)/(4)x- (18)/(4)) \\ 4y=-3x-18 \\ 4y+3x=-3x-18+3x \\ 4y+3x=-18 \\ 3x+4y=-18`