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Factor the polynomial 6b^2-17b+10
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Factor the polynomial 6b^2-17b+10

User Suitedupgeek
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6b ^ 2-17b +10 \\ \\\Delta = b^(2)-4ac = (-17)^(2)-4*6*10=289-240=49\\ \\x_(1)=(-b-√(\Delta ))/(2a) =(17- √(49))/(2*6)=(17-7)/(12)= (10)/(12)=(5)/(6)\\ \\x_(2)=(-b+√(\Delta ))/(2a) =(17+ √(49))/(2*6)=(17+7)/(12)= (24)/(12)=2 \\ \\ Answer : \ x=(5)/(6) \ \ or \ \ x=2


User Gevious
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