Question

If 166.05 J of heat energy was added to a lead sinker with a mass of 143 grams, then what is the total temperature change for the lead sinker? Assume the specific heat of lead is 0.129 J/g°C .A.) 3060 °CB.) 309 °CC.) 0.111 °CD.) 9 °C

Answer 1

Question

If 166.05 J of heat energy was added to a lead sinker with a mass of 143 grams, then what is the total temperature change for the lead sinker? Assume the specific heat of lead is 0.129 J/g°C.

Procedure

The question asks for a temperature change and provides the specific heat, mass, and added energy to a lead sinker. Therefore it is useful to use the specific heat equation to determine the temperature change.

`Q=mc\Delta T`

Where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the temperature change.

Rearranging the variables in the equation

`\Delta T=(Q)/(mc)`

Solving the equation

ΔT= 9.0 °C

Answer

ΔT= 9.0 °C (Answer D)