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What are the zeros of -3x^2+10x+12
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What are the zeros of -3x^2+10x+12

User Alucard
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-3x^2+10x+12=0\\ \Delta=10^2-4\cdot(-3)\cdot12=100+144=244\\ √(\Delta)=√(244)=2√(61)\\ x_1=(-10-2√(61))/(2\cdot(-3))=(-10-2√(61))/(-6)=(5+√(61))/(3)\\ x_2=(-10+2√(61))/(2\cdot(-3))=(-10+2√(61))/(-6)=(5-√(61))/(3)\\
User Thisisnabi
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