Question

What is the mass in grams of 1.73 moles CaH2

Answer 1

To calculate the mass of 1.73 moles of CaH2, mulitply the number of moles by the molar mass of the substance (42.10 g/mol), resulting in a mass of 72.833 grams of calcium hydride.

Step-by-step explanation:

The mass in grams of 1.73 moles of calcium hydride (CaH2) can be calculated using the molar mass of CaH2 and dimensional analysis.

To find the mass, we will use the molar mass of CaH2, which is the sum of the atomic mass of calcium (Ca, approximately 40.08 g/mol) and twice the atomic mass of hydrogen (H, approximately 1.01 g/mol). This gives us a molar mass of 40.08 g/mol + 2(1.01 g/mol) = 42.10 g/mol for CaH2. By multiplying the number of moles by the molar mass, we can determine the mass of the sample.

Mass of CaH2 = 1.73 moles × 42.10 g/mol = 72.833 grams of CaH2.

Answer 2

The mass of 1.73 moles CaH2 is 72.82 grams. The molar mass of CaH2 is 42.08 g/mol. This means that there are 42.09 grams in 1 mol. So, x grams will be in 1.73 mol of CaH2. Let's make a proportion: 42.09 g : 1 mol = x : 1.73 mol. x = 42.09 g * 1.73 mol : 1 mol. x = 72.82 g.