Question

Determine the quantity of work done when a crane lifts a 100-N block from 2 m above the ground to 6 m above the ground.

A.
100 J

B.
200 J

C.
400 J

D.
600 J

Answer 1

400 J

Step-by-step explanation:

I just took the test and can confirm this.

Answer 2

C. 400 J

Step-by-step explanation:

In physics, work is defined as

`W=F * \Delta d`

Where
`W` is the word done,
`F` is the force that move the object and
`\Delta d` is the change of the position of the object.

In this case, we have

`F= 100 \ N`

`\Delta d= 6m - 2m = 4m`, remember that the difference refers to the actual subtraction between the final point and the initial point of the object.

Replacing these values, we have

`W= 100 \ N * 4m\\W=400 \ Joules`

Therefore, the right answer is C. The work done is 400 Joules