58.8k views
3 votes
Look Down Below For question:

Look Down Below For question:-example-1

2 Answers

4 votes
Used brute force to figure this one out and got lucky at t=12.

What you need to know:


d=\left| x-y \right|

t = time travelled (in hours)

x = distance passenger train has travelled

y = distance cattle train has travelled

d = distance between both trains in km

------------------------------------

RESULTS AND TIME SNAPSHOTS:

When:

t=0, x=0, y=0, d=0

t=2.4, x=70.08, y=0, d=70.08

t=4.8, x=140.16, y=87.6, d=52.56

t=7.2, x=210.24, y=175.2, d=35.04

t=9.6, x=280.32, y=262.8, d=17.52

t=12, x=350.4, y=350.4, d=0 <-------

So your answer is 12 hours.
User Tano
by
8.5k points
3 votes
the cattle train
speed - 36.5 km/h
time - x h

the passenger train
speed - 29.2 km/h
time - (2.4+x) h

The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.


36.5 * x=29.2 * (2.4+x) \\ 36.5x=70.08+29.2x \\ 36.5x-29.2x=70.08 \\ 7.3x=70.08 \\ x=(70.08)/(7.3) \\ x=9.6 \\ \\ 2.4+x=2.4+9.6=12

The passenger train travelled for 12 hours before the cattle train caught up.
User VeikkoW
by
7.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories