Question

Find the zeros of the function f(x)=2x^2-7x-30

Answer 1

`2x^2-7x-30=0 \\ \\ a=2 \\ b=-7 \\ c=-30 \\ b^2-4ac=(-7)^2-4 * 2 * (-30)=49+240=289 \\ \\ x=(-b \pm √(b^2-4ac))/(2a)=(-(-7) \pm √(289))/(2 * 2)=(7 \pm 17)/(4) \\ x=(7-17)/(4) \ \lor \ x=(7+17)/(4) \\ x=(-10)/(4) \ \lor \ x=(24)/(4) \\ x=-(5)/(2) \ \lor \ x=6 \\ \boxed{x=-2.5 \hbox{ or } x=6}`