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F(x) = x2 + 10х=What is the average rate of change of fover the interval [-2, -1]?

User E Ciotti
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1 Answer

19 votes
19 votes

Given


f(x)=x^2+10

To find the average rate of change of f over the interval [-2,-1].

Step-by-step explanation:

It is given that,


f(x)=x^2+10

The average rate of change is given by,


Average\text{ }rate\text{ }of\text{ }change=(f(b)-f(a))/(b-a)

That implies,


\begin{gathered} f(-1)=(-1)^2+10 \\ =1+10 \\ =11 \end{gathered}

Also,


\begin{gathered} f(-2)=(-2)^^2+10 \\ =4+10 \\ =14 \end{gathered}

Therefore,


\begin{gathered} Average\text{ }rate\text{ }of\text{ }change=(f(-1)-f(-2))/(-1+2) \\ =(11-14)/(1) \\ =-3 \end{gathered}

Hence, the average rate of change is -3.

User Photon Point
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