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Look below for question:-example-1
User Ed Dore
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first we find width or legnth,
then we determine which wire is shortest
a wire=264

legnth used for rectangle=x

legnth used for square=264-x=y

reactangle=2legnh+2width=2(l+w)
l=2w-4
subsitute
2(2w-4+w)=recangle perimiter=4w-8+2w=6w-8



square=y
legnth=width
legnth=rectangleleghtn+width (rectangle l+w=3w-4)
4legnth=perimiter=12w-16


recangle perimiter=6w-8
square perimiter=12w-16
x+y=264
(6w-8)+(12w-16)=legnth of wire toatl
18w-24=total widght=264
18w-24=264
add 24 to both sides
18w=288
divide both sides by 18
w=16
perimter of square=4(l+w)
l=2w-4
l=2(16)-4
l=28
perimiter of square 4(28+16)=4(44)=176
176=y
x+y=264
x+176=264
subtract 176 from both sides
x=88
rectangle=88
88<176

rectangle is shorter wire which is 88 cm in total legnth

88cm is answer
User Hojin
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